By Virgil Moring Faires
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Extra info for Thermodynamics of heat power
Ft. / lb. The increase of internal energy is 40 Btu/ lb. K = O. How much heat is transferred? SOLUTION . The forms of energy to be considered are flow work, internal energy, work, and of course heat. For 1 lb . W/ = W j2 778 = 555 B . 55 . 7 Btu/ lb. 24 CONSERV A liON OF ENERGY [Ch. ; and since the internal energy increases, flu = U2 - Ul = +40 Btu/ lb. , where the negative sign indicates that heat is rejected by the system. Some air compressors have water jackets for the purpose of cooling the air during compression, so the negative sign would be expected.
Since the foot-pound is a relatively STEADY FLOW EQUATION WITH ENTHALPY § 23] 21 small unit for most engineering purposes, we use the British thermal unit (Btu) more often and Joule's constant J to show the conversion where necessary. Also, (7 A) may represent one pound or any number of pounds of fluid flowing during some elapsed time. You should fix in mind the meaning of (7) and the method of determining the value of each term. W I = (P 2 V 2 - P1V1)/J Btu. U are given later. There is no change in the convention of signs as previously given for the nonflow equation (5), p.
46. A process follows the relation pVn = C, where nand C are constants. Show that and 47. The heat rejected by 10 lb. of each of the following gases is 200 Btu: nitrogen, helium, argon. For each gas [Ch. 3 at 80°F, what is the change of temperature and the final temperature \a) if the pressure remains constant, (b) if the volume remains constant? Ans. 5°F for N 2; (b) t2 = 346°F for A. 48. (a) If 1400 Btu are transferred to a certain mass of nitrogen in order to change its temperature 100°F at constant pressure, how much heat is necessary for the same temperature change at constant volume?